Awesome. I’ll incorporate these calculations into the design.

]]>At 25 mm from your 72 Gauss coil I get approx 4.74 Gauss. Assuming Te of 2.5 KeV, I come up with a V-Te of 1.88E5 mm/s and W-ce of 8.35E8 rad/s, which results in a gyro radius of .001mm…hmm…told you I sucked at Algebra. I’m pretty sure V-Te should be much higher.

]]>http://en.wikipedia.org/wiki/Electron_gyro_radius

is the radius of the circular motion of an electron in the plane perpendicular to the magnetic field:

Rge=V-Te / w-ce. We’re talking about a V-Te of whatever your electron injection temperature is. w-ce is 1.76×10^7rad/s *B, where B is the strength of your magnetic field (perpendicular component for your application) at that point, and whatever unit conversions you have to do to come back out with mm.

“That point” for your application should be the “center” of the coil corner, and for the electron heading straight out of corner from the center of the device, the perpendicular component B would be the actual magnetic field strength. I suck at algebra so I’d use ephi or another Biot-Savart calculator to figure it out. Try searching talk-polywell for a Biot-Savart calculator.

]]>I’m aware of the spacing consideration, but I have not yet incorporated them into my design. I don’t know how to calculated the electron gyro radius. I also don’t know how the dodecahedral shape plays into spacing.

Can you help me with those calculations?

]]>How did you figure the correct corner spacing of the coils? According to Bussard & Nebel it’s a critical parameter for getting a good Beta and for keeping losses to coils at a minimum.

It should be between 6-9 electron gyro radius (Rge)at this point but how did you figure that without knowing the estimated field strength at that location?

]]>*MSimon, are you saying that my cable will support 80 –110 Amps regardless of length?*

Yes. Like any other conductor (of sufficient length) it is the area of the wire that matters.

]]>*Yes. Like any other conductor (of sufficient length) it is the area of the wire that matters.*

*Engineering Current Density (Je) = 21 –29 kA/cm2 *

Ic is what your piece of wire will actually support. Je is what you could get with 1 sq cm of wire X meters long. Which says your wire is about .005 sq cm effective area. Put your mike to it and see if that isn’t about right.

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